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Odishatv Bureau

New Delhi: Here's another big opportunity for government job aspirants. The Union Public Service Commission (UPSC) has released a recruitment notification inviting applications from candidates for multiple positions including Livestock Officer, Assistant Legal Adviser, Deputy Fire Adviser, Medical Officer/ Research Officer and other posts. Interested and eligible candidates can apply for the positions before the deadline.

The last date for submission of application is September 12, 2019.

UPSC Recruitment 2019 Vacancy Details:

Livestock Officer – 04 Posts
Assistant Legal Adviser – 05 Posts
Deputy Fire Adviser – 01 Posts
Medical Officer/ Research Officer – 01 Posts
Assistant Director – 01 Posts

Educational Qualification

Livestock Officer: Bachelor’s degree in Veterinary Science and Animal Husbandry as listed in the First and Second Schedule of the Indian Veterinary Council Act. 1984 from a recognised university or institution. Besides, registration in the Veterinary Council of India or Veterinary Council of States.
Assistant Legal Adviser: Degree in law from a recognized University or equivalent. Note: Equivalent degree is LLB OR Master’s Degree in law from a recognized University or equivalent.
Deputy Fire Adviser: Bachelor Degree in Fire Engineering from a recognized University/ Institute.
Medical Officer/ Research Officer: Any Graduate
Assistant Director – BVSC

Selection Process: Selection of candidates will be done based on their performance in a Recruitment Test followed by Interview.


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